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Concavity and inflection points

A graph is concave up where its slope is increasing (f″ > 0) and concave down where its slope is decreasing (f″ < 0). A point of inflection is where the concavity changes.

By the Calcist team · Updated October 26, 2026 · About a 5-minute read

Concave up vs concave down

Concave upConcave down
Slope f′IncreasingDecreasing
Second derivative f″PositiveNegative
ShapeBends upward, like a cupBends downward, like a cap
Simple exampley = x²y = −x²

Test for concavity. If f is twice differentiable on an interval I, then f is concave up on I if f″(x) > 0 for all x in I, and concave down on I if f″(x) < 0 for all x in I.

What is a point of inflection?

If f is continuous at a and changes concavity at a, the point (a, f(a)) is an inflection point. To find candidates, look where f″(x) = 0 or f″ is undefined, then check that the sign of f″ actually changes there.

f″ = 0 is not enough. For f(x) = x4, f″(x) = 12x² is 0 at x = 0, but it's positive on both sides, so the graph is concave up throughout and there's no inflection point.

Example 1: f(x) = x³ − 6x² + 9x + 30

  1. First derivative: f′(x) = 3x² − 12x + 9.
  2. Second derivative: f″(x) = 6x − 12.
  3. Solve f″(x) = 0: x = 2.
  4. Test each side. At x = 0, f″(0) = −12 < 0. At x = 3, f″(3) = 6 > 0.
  5. So f is concave down on (−∞, 2) and concave up on (2, ∞).
  6. The concavity changes at x = 2, and f(2) = 8 − 24 + 18 + 30 = 32, so the inflection point is (2, 32).

The second derivative test

Suppose f′(c) = 0 and f″ is continuous near c.

  • If f″(c) > 0, f has a local minimum at c (concave up, like the bottom of a cup).
  • If f″(c) < 0, f has a local maximum at c.
  • If f″(c) = 0, the test is inconclusive. Use the first derivative test instead. For example, x4 has a minimum at 0, −x4 has a maximum, and x³ has neither, yet all three have f″(0) = 0.

Example 2: f(x) = x5 − 5x³

  1. f′(x) = 5x4 − 15x² = 5x²(x² − 3). Critical points: x = 0 and x = ±√3.
  2. f″(x) = 20x³ − 30x = 10x(2x² − 3).
  3. At x = −√3: f″ = −30√3 < 0, so a local maximum.
  4. At x = √3: f″ = 30√3 > 0, so a local minimum.
  5. At x = 0: f″(0) = 0, inconclusive. f′ is negative on both sides of 0 (5x² ≥ 0 and x² − 3 < 0 near 0), so f is decreasing through 0: no local extremum.
  6. Inflection points: f″ = 0 at x = 0 and x = ±√(3/2), and f″ changes sign at each, so all three are inflection points.

Reading concavity in the real world

If f is a position, f″ is acceleration: concave up means speeding up in the positive direction. On a growth curve, an inflection point is where growth stops accelerating and starts slowing down.

Find inflection points with the inflection point calculator, compute f′ and f″ with the derivative calculator, and see the shape on the graphing calculator. For the first-derivative side of the picture, see the mean value theorem.

Sources: OpenStax Calculus Volume 1, 4.5 Derivatives and the Shape of a Graph.

Every worked example on this page was checked with Calcist's own engine and an independent reference.

Questions people ask

What does concave up mean?

The graph bends upward like a cup: its slope is increasing, and f″(x) is positive.

What is the difference between concave up and concave down?

Concave up means the slope is increasing (f″ positive); concave down means the slope is decreasing (f″ negative).

What is a point of inflection?

A point where the graph is continuous and changes concavity, from concave up to concave down or the reverse.

Is every point where f″ = 0 an inflection point?

No. The sign of f″ must change. For x⁴, f″(0) = 0 but the graph is concave up on both sides.

What is the second derivative test?

At a critical point c, a positive f″(c) means a local minimum, a negative f″(c) a local maximum, and f″(c) = 0 is inconclusive.