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Double-angle and half-angle identities

These identities rewrite trig functions of 2θ or θ/2 in terms of θ. They give exact values like sin 15°, simplify expressions, and turn sin² and cos² into forms you can integrate.

By the Calcist team · Updated October 29, 2026 · About a 6-minute read

Double-angle formulas

sin 2θ = 2 sin θ cos θ
cos 2θ = cos² θ − sin² θ = 2cos² θ − 1 = 1 − 2sin² θ
tan 2θ = 2 tan θ / (1 − tan² θ)

They come from the sum formulas with both angles equal: sin(θ + θ) = sin θ cos θ + cos θ sin θ = 2 sin θ cos θ, and cos(θ + θ) = cos² θ − sin² θ. The other two forms of cos 2θ use sin² θ + cos² θ = 1.

Half-angle formulas

sin(θ/2) = ±√((1 − cos θ)/2)
cos(θ/2) = ±√((1 + cos θ)/2)
tan(θ/2) = (1 − cos θ)/sin θ = sin θ/(1 + cos θ)

The sign depends on the quadrant of θ/2, not θ. The tan formulas need no ± sign.

Power-reducing formulas

sin² θ = (1 − cos 2θ)/2    cos² θ = (1 + cos 2θ)/2    tan² θ = (1 − cos 2θ)/(1 + cos 2θ)

These are the cos 2θ formulas solved for sin² θ and cos² θ. They're the standard way to integrate sin² x: ∫sin² x dx = ∫(1 − cos 2x)/2 dx = x/2 − sin(2x)/4 + C.

Worked examples

1. Exact value of sin 15°. 15° is half of 30°, and it's in the first quadrant, so use the + sign: sin 15° = √((1 − cos 30°)/2) = √((1 − √3/2)/2) = √(2 − √3)/2. This also equals (√6 − √2)/4 ≈ 0.258819.

2. Exact value of cos 22.5°. cos 22.5° = √((1 + cos 45°)/2) = √((1 + √2/2)/2) = √(2 + √2)/2 ≈ 0.92388.

3. tan(π/8). tan(π/8) = (1 − cos(π/4))/sin(π/4) = (1 − √2/2)/(√2/2) = √2 − 1 ≈ 0.414214.

4. Using a known sine. If sin θ = 3/5 and θ is in quadrant II, then cos θ = −4/5. So:

  • sin 2θ = 2(3/5)(−4/5) = −24/25
  • cos 2θ = (−4/5)² − (3/5)² = 16/25 − 9/25 = 7/25
  • tan 2θ = sin 2θ / cos 2θ = −24/7

Check: (−24/25)² + (7/25)² = 576/625 + 49/625 = 1, as it should.

5. Simplifying. (sin 2x)/(1 + cos 2x) = (2 sin x cos x)/(2cos² x) = tan x.

Solving equations with double angles

Replacing sin 2x or cos 2x with a single-angle form usually lets you factor. Solve sin 2x = sin x for 0 ≤ x < 2π:

  1. Rewrite: 2 sin x cos x = sin x.
  2. Move everything to one side and factor. Don't divide by sin x, or you'll lose solutions: sin x (2 cos x − 1) = 0.
  3. sin x = 0 gives x = 0 or π. cos x = 1/2 gives x = π/3 or 5π/3.
  4. So x = 0, π/3, π, 5π/3.

For cos 2x + cos x = 0, choose the form of cos 2x with only cosines: 2cos² x − 1 + cos x = 0 factors as (2 cos x − 1)(cos x + 1) = 0, giving x = π/3, π and 5π/3.

Quick reference

Angle θsin 2θcos 2θsin(θ/2)cos(θ/2)
30°√3/21/2(√6 − √2)/4(√6 + √2)/4
45°10√(2 − √2)/2√(2 + √2)/2
60°√3/2−1/21/2√3/2
90°0−1√2/2√2/2

Common mistakes

  • sin 2θ is not 2 sin θ. For θ = 30°, sin 60° ≈ 0.866 but 2 sin 30° = 1.
  • Choosing the half-angle sign from θ instead of θ/2. If θ = 300°, θ/2 = 150° is in quadrant II, so sin(θ/2) is positive and cos(θ/2) is negative.
  • Mixing degrees and radians on a calculator. See degrees and radians.

Read exact values off the unit circle, evaluate trig functions with the scientific calculator, and find angles from values with the inverse trig calculator. To differentiate the results, see the derivative rules table.

Sources

Every worked example on this page was checked independently with SymPy.

Questions people ask

What is the double-angle formula for sin?

sin 2θ = 2 sin θ cos θ.

What are the three forms of cos 2θ?

cos² θ − sin² θ, 2cos² θ − 1, and 1 − 2sin² θ. They're equal because sin² θ + cos² θ = 1.

What is the half-angle formula for sine?

sin(θ/2) = ±√((1 − cos θ)/2), with the sign set by the quadrant of θ/2.

What is sin 15° exactly?

(√6 − √2)/4 ≈ 0.258819, from the half-angle formula with θ = 30°.

How do you integrate sin² x?

Use the power-reducing identity sin² x = (1 − cos 2x)/2. The integral is x/2 − sin(2x)/4 + C.